Question

find the ratio of the number of atoms present in 16g of oxygen and 32 g of ozone

Answer 1

No of atoms in 32 g O2=2×Na
In 16g=2×Na/32×16=Na atoms

In 48 g of O3 atoms=3×Na
In 32 g=3×na/48×32
=2Na
Ratio=1:2

Note:here Na refers to Avogadro no. Or 6.022×10^23