Question

find the square of 491 use identity

Answer 1

The value of $491^2$ is equal to 241081.

Step-by-step explanation:

We have,

$491^2$

To find, the value of $491^2$ = ?

∴ $491^2$

= $(500-9)^{2}$

Using the algebraic identity,

$(a-b)^{2}=a^{2}-2ab+b^2$

∴ $(500-9)^{2}= (500)^{2}-2(500)(9)+9^{2}$

= 250000 - (1000)(9) + 81

= 250000 - 9000 + 81

= 241000 + 81

= 241081

Thus, the value of $491^2$ is equal to 241081.