Find the relation between x and y , such that (x, y) is equidistant from (5,1) and ( -1,5)
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Step-by-step explanation:
let AB is equidistant from AC then; AB=AC using distance formula, (x1‑x2)^2+(y1‑y2)^2=(x1‑x2)^2+(y1‑y2)^2
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