Find the sum of n terms of the series whose nth term as (2n-1)2 ?
raoatchut191:
is it a.p
Answers
Answered by
4
tn = (2n-1)2
t₁ = 2
t₂ = 6
t₃=10
the series is in a.p.
d=4
a=2
sum of n terms of ap =n/2 [ 2a+(n-1)d ]
=n/2 [ 4+ 4n-4 ]
=n/2 [ 4n ]
=4n²/2
=2n²
t₁ = 2
t₂ = 6
t₃=10
the series is in a.p.
d=4
a=2
sum of n terms of ap =n/2 [ 2a+(n-1)d ]
=n/2 [ 4+ 4n-4 ]
=n/2 [ 4n ]
=4n²/2
=2n²
Answered by
3
tn = (2n-1)2
t₁ = 2
t₂ = 6
t₃=10
the series is in a.p.
d=4
a=2
sum of n terms of ap =n/2 [ 2a+(n-1)d ]
=n/2 [ 4+ 4n-4 ]
=n/2 [ 4n ]
=4n²/2
=2n²
=2n*2n
=4n
t₁ = 2
t₂ = 6
t₃=10
the series is in a.p.
d=4
a=2
sum of n terms of ap =n/2 [ 2a+(n-1)d ]
=n/2 [ 4+ 4n-4 ]
=n/2 [ 4n ]
=4n²/2
=2n²
=2n*2n
=4n
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