Find the three consecutive even numbers whose squares have a sum of 221.. Please help me.
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it is impossible as
square of a even no. is even (take any even no.)
so square of all no. must be even
now sum of even no. is also even - which is given as odd so. it's impossible
square of a even no. is even (take any even no.)
so square of all no. must be even
now sum of even no. is also even - which is given as odd so. it's impossible
ThePlusOfminus:
Please solve it further
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You mean that the question is wrong
m i right???
yess
I will go through it tqvm
Good night bro
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Three consecutive even integers can be represented by x, x+2, x+4. The sum is 3x+6, which is equal to 108. Thus, 3x+6=108.
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