Question

find the value of 8x+2y-3xy+3xy+1/2 x^2 for x=2,y=-1​

Answer 1

given that,

8x+2y-3xy+1÷2 x^2.

x=2, y=1

so,8×2+2×1-3×2×1+1÷2 2^2

16+2-6+1÷2 2^2

13÷2 2^2

13÷2 2×2

13÷2×4

13÷8

approximately =1.625.