Question

Find the value of a and b here.(√2+√3)/(3√2+2√3)=a-b√6

Answer 1

rationalize and put the values of a and b.

Answer 2

Answer:

a=0 and b=-1/√6

Step-by-step explanation:

Given (√2+√3)/(3√2+2√3)=a-b√6

LHS=[(√2+√3)/(3√2+2√3)]*[(3√2-2√3)/(3√2-2√3)]

      =[(√2+√3)(3√2-2√3)/(18-12)]         (∵(x+y)(x-y)=x²-y²)

      =(6-2√6+3√6-6)/6

      =(√6)/6

⇒a=0 and b=-1/√6