Question

find the value of a-b when a2+b2 =108 ab =52​

Answer 1

Answer:

a-b = 2

Step-by-step explanation:

(a-b)^2 = a^2 + b^2 - 2ab

(a-b)^2 = 108 -2*52 ( a^2 + b^2 = 108 and ab = 52)

(a-b)^2= 108-104

(a-b)^2 = 4

a-b = 2 ( Squaring both sides )

Answer 2

Answer:

(a-b) = 2

Step-by-step explanation:

(a-b)^2 = a^2 +b^2 - 2ab

(a-b)^2 = 108 - 2*52

(we know a^2+b^2=108 and ab = 52)

(a-b)^2 = 108 -104

(a-b)^2 = 4

(a-b)^2 = 2^2

(square rooting on both sides)

therefore , (a-b) = 2