Question

Find the value of K for which the roots of quadratic equation are equal (k-4) x^2 + (k-4)x +4=0

Answer 1

Answer:

Step-by-step explanation:

(k-4)x²+2(k-4)x+2=0

IF BOTH THE ROOTS ARE EQUAL;THEN DISCRIMINANT ⇒b²=4ac

then a=k-4; b=2(k-4) ;c=2; substituting the values

(2k-8)²=4×(k-4)×2

4k²+64-32k=8k-32

4k²-40k+96=0

k²-10k+24=0

(k-4)(k-6)=0

k=4,6