Find the value of k, if x=3 is a factor of
k²x³-kx² + 3kx-k
Answers
Answered by
50
Let f(x) be the given polynomial.
f(x)=k²x³-kx²+3kx-k
Given that x=3
If (x - @) is a factor of a polynomial,then @ is zero of a polynomial
So,
f(x)=f(3)
Substituting the required value,
f(3)=k²x³-kx²+3kx-k
→0 = k²(3)³-k(3)²+3k(3)-k
→0=27k²-9k+9k-k
→27k²-k=0
→k(27k-1)=0
→k=0 or 27k=1
→k=1/27 or 0
Answered by
42
Given p(x) = k²x³ - kx² + 3kx - k
given one zero of p(x) = 3
then,
p(3) = 0
k²(3)³ - k(3)² + 3k(3) - k = 0
27k² - 9k + 9k - k = 0
27k² - k = 0
k(27k - 1) = 0
27k - 1 = 0
27k = 1
k = 1/27
so,
k = 1/27
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