Find the value of sin2A when(assuming 0
atul103:
sin2a=0
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Sin (2A) = 2sinAcosA = 2tanA/1+tan^2A
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sin 2A=0
sin 2A=sin0
2a=0
a=0
because sin 0=0
sin 2A=sin0
2a=0
a=0
because sin 0=0
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