find the value of sin60°/cos²45°-cot30°+15(cos 90°)
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Solution :
____________________
i ) sin60° = √3/2
ii ) cos 45 = 1/√2
iii ) cot 30° = √3
iv ) cos 90° = 0
__________________
Now ,
sin60/cos²45 -cot30+15(cos90)
= (√3/2)/(1/√2)²-√3+15×0
= √3 - √3
= 0
•••••
____________________
i ) sin60° = √3/2
ii ) cos 45 = 1/√2
iii ) cot 30° = √3
iv ) cos 90° = 0
__________________
Now ,
sin60/cos²45 -cot30+15(cos90)
= (√3/2)/(1/√2)²-√3+15×0
= √3 - √3
= 0
•••••
Cot 30° =√3
Therefore answer is 0.
Yes , I corrected the mistake . Thank you.
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