find the value of x and y if, x+√y=7and x-√y=11
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Answered by
1
√x+y=7
x+√y=11
√x=7-y
√y=11-x
the square root of a number is always the positive square root
therefore y can't be greater than 7 and x can't be greater than 11
look at the perfect squares 1, 4, 9, 16
assuming x and y are perfect squares and a little trial and error...
x=9 and y=4
x+√y=11
√x=7-y
√y=11-x
the square root of a number is always the positive square root
therefore y can't be greater than 7 and x can't be greater than 11
look at the perfect squares 1, 4, 9, 16
assuming x and y are perfect squares and a little trial and error...
x=9 and y=4
Answered by
0
x+√y=7 1)
x-√y=11 2)
Now adding
Then 2x=18
x=9 ans put in eq1)
x+√y=7
9 +√y=7
√y=7-9
√y=-2
On sq both sides
(√y)sq =(-2)sq
y= 4 ans
x-√y=11 2)
Now adding
Then 2x=18
x=9 ans put in eq1)
x+√y=7
9 +√y=7
√y=7-9
√y=-2
On sq both sides
(√y)sq =(-2)sq
y= 4 ans
jjjMunnakumar1:
you have make mistakes to answr my question.my questions is x+√y=7 and y+√x=11.so find the value of x and y
Hey then it's ur mistakes u have written wrong ques
Jus see ur ques
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