Question

Find the value of x. Class 7th cbse​

Answer 1

$</p><p></p><p></p><p>\rightarrow \qquad \left( \frac{2}{9} \right)^{-6} \times \left( \frac{2}{9} \right)^{3} = \left( \frac{2}{9} \right)^{2x - 1}</p><p></p><p>\\ \\</p><p></p><p>\rightarrow \qquad \left( \frac{2}{9} \right)^{-6 + 3} =\left( \frac{2}{9} \right)^{2x - 1} \qquad \left( \because a^{m} \times a^{n} = a^{m + n} \right)</p><p></p><p>\\ \\</p><p>\rightarrow \qquad \left( \frac{2}{9} \right)^{-3} =\left( \frac{2}{9} \right)^{2x - 1}</p><p></p><p>\\ \\</p><p></p><p>\mathtt{ On \: comparing } \\ \\</p><p></p><p>\rightarrow \qquad -3 = 2x - 1 \\ \\</p><p></p><p>\rightarrow \qquad -2 = 2x \\ \\</p><p></p><p>\rightarrow \qquad x = - \frac{\cancel{2}}{\cancel{2}} \\ \\</p><p></p><p>\Rightarrow \qquad x = -1 </p><p></p><p></p><p>$

Answer : -1

Answer 2

Answer:

-1

Step-by-step explanation:

((2/9)^-6) × ((2/9)^3) = ((2/9)^2x-1)

LHS

(9/2)^6 ×(2/9)^3

(9/2)^3

(2/9)^-3

RHS

(2/9)^2x-1

-3 = 2x-1

-3+1=2x

-2/2=x

-1 =x