Question

Find the value os sin2A,when
a)sinA=1/2

Answer 1

Step-by-step explanation:

this is the answer of your question

Answer 2

Answer:

sin²A + cos²A = 1

∴ cos²A = 1 - sin²A

∴ cos²A = 1 - (1/2)²

∴ cos²A = 1 - 1/4

∴ cos²A = 3/4

cosA = $\sqrt{3}$/2 ....taking sq. rt

Now,

sin2A = 2sinAcosA

          = 2(1/2)($\sqrt{3}$/2)

 sin2A = $\sqrt{3}$/2

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