Question

Find the values of k for quadratic equation 2x^2+kx+k=0

Answer 1

Answer :- k = 0 , k = 8

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Step by step explanation :-

Equation :-

$2 {x}^{2} + kx + k = 0$

calculating the discriminant :-

D = b^2 - 4ac

= k^2 - 4 x 2k

= k^2 - 8k

Now,

k^2 - 8k = 0

factoring the k from the equation :-

k ( k - 8 ) = 0

Note:- if the product of the factors equals 0, then at least one the factor is equal to 0.

So, k = 0

and

k - 8 = 0

k = 8

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Final solutions are,

k = 0 and k = 8

Answer 2

Therefore the value of k=0 and k=8 .