Question

find the zeroes of p(z)=z^2-27​

Answer 1

Answer:

Here is your answer bro..

Step-by-step explanation:

p(z)=z^2-27

p(1)=1^2-27

=1-27=

=-26

p(2)=2^2-27

= 4-27

-23

Thnx

Answer 2

The zeros of the polynomial is $z=3\sqrt{3},-3\sqrt{3}$

Step-by-step explanation:

Given : Polynomial $p(z)=z^2-27$

To find : The zeros of the polynomial ?

Solution :

To find the zeros we equate the polynomial to zero.

i.e. $p(z)=0$

$z^2-27=0$

$z^2=27$

$z=\sqrt{27}$

$z=\pm3\sqrt{3}$

Therefore, the zeros of the polynomial is $z=3\sqrt{3},-3\sqrt{3}$

#Learn more

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