Question

find the zeroes of quadratic polynomial h(t)=t2-15

Answer 1

 
t2 - 15 = (t + √15)( t - √15)

therefore      t+ √15 = 0

i.e.     t =    - √15

similarly        t - √15 = 0

and    t =   √15

so the zeros are        √15   and    - √15

Answer 2

Given,

• The polynomial $t^2-15$ is given.

To find,

• We have to find the zeros of the quadratic polynomial.

Solution,

We can simply find the zero of the quadratic polynomial by equating the polynomial to 0.

                     $t^2-15$ = 0

Transposing -15 from LHS to RHS, we get

                               t² = 15

Now, taking square root on both sides, we get

                             $\sqrt{t^2} = \sqrt{15}$

On simplification, we get

                                t  =± $\sqrt{15}$

Hence, the zeroes of the quadratic polynomial h(t)=t²-15 is ± $\sqrt{15}$.