Question

Find the zeroes of

$4x {}^{2} - 3x + 7$
In Zeroes of a polynomial
​

Answer 1

Answer:

x -1 = 0

x =1

p ( x ) = 4x ^2 - 3x +7

.

p (1) = 4(1)^2 - 3 (1) +7

= 4-3+7 = 4 -4 = 0

so , x - 1 is the zero of the polynomial ..

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Answer 2

Answer:

$4 {x}^{2} - 3x + 7 = 0 \\ 4 {x }^{2} - 4x - 7x + 7 = 0 \\ 4x(x - 1) - 7(x - 1) =0 \\ (4x - 7)(x - 1) = 0 \\ x = \frac{7}{4} \: \: \: \: \: x = 1$

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