Question

find the zeroes of the polynomial class 10 4g^2-25

Answer 1

Heya!!
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Given that ,

$p(x) = > 4g {}^{2} - 25 \\ \\ \\ = > > (2g) {}^{2} - (5) {}^{2} \\ \\ = > > using \: a {}^{2} - b {}^{2} = (a + b)(a - b) \\ \\ \\ = > > (2g - 5)(2g + 5) \\ \\ = > > 2g = 5 \: \: \: \: 2g = - 5\\ \\ g = \frac{5}{2} \: \: g = \frac{ - 5}{2}$

Hence the zeroes are -5/2 and 5 / 2


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