find the zeroes of x2 - x -4?
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x²+(-x)+(-4)= 0 ; comparing with ax²+bx+c = 0
a = 1 ; b = -1 ; c = -4
by sridharacharya formula,
x = -b±√(b²-4ac) /2a = [ 1 ±√(1+16)] /2 = 1 ± 4.13/2
•°• x = 5.13/2 , x = -3.13/3
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