find two solution of the following equation for 4x + 3y=12
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Answered by
3
the solutions of polynomial 4x+3y=12 is:
if X=0, then y=12/3=4
if y=0, then x =12/4=3
if X=0, then y=12/3=4
if y=0, then x =12/4=3
Answered by
6
Answer: let x = 3
. : 4x+3y=12
4X3 + 3y =12
12+3y=12
3y=12-12
3y=0
y=0-3
y= -3
..........
Let y= 4
4x+3y=12
4x+3X4=12
4x+12=12
4x=12-12
4x=0
x=0-4
x= -4
Hope it will help you
Step-by-step explanation:
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