Question

Find what length of canvas 2m in width is required to make a conical tent 8m in diameter & 5.6m in slant height ,also find the cost of the canvas at the rate of Rs.19.20 per meter

Answer 1

Given :

Length of the canvas (L)=2m

Let the width of the canvas = B m

Dimensions of a conical tent:

Diameter (d) = 8 m

radius (r) = d/2

=> r = 8/2 = 4 m

Slant height (l) = 5.6 m

According to the problem given,

Area of the canvas = Curved surface area of the conical tent

=> L × B = πrl

=> 2 × B = (22/7) × 4 × 5.6

=> B = (22×4×5.6)/(2×7)

After cancellation, we get

=> B = 35.2 m

Now ,

Area of canvas required for

conical tent (A) = L×B

= 2m × 35.2 m

= 70.4 m²

It is given that ,

cost of the canvas 1 m² is equal

to Rs 19.20

Cost of the canvas 70.4 m²

= 19.20 × 70.4

= Rs 1351.68

Therefore,

Width of the canvas (B) = 35.2m

Cost of the canvas = Rs 1351.68

••••

Answer 2

Answer:

Width of the canvas is 35.2 m and the cost of the canvas is Rs 1351.68.

Step-by-step explanation:

Length of the canvas L = 2 m

Width of the canvas = B m

Diameter of the conical tent d=8m

Radius r= d/2= 8/2 =4m

Slanting height l=5.6m

Area of canvas = curved surface area of the conical tent

L x B = πrl

2 x B = 22/7 X 4 X 5.6

B= 22/14 x 4 X 5.6

 = 35.2 m

Therefore area of canvas = L x B

                                          = 2m x 35.2m  $=70.4 \mathrm{m}^{2}$

Cost of the canvas per meter = Rs 19.20

                                         $=70.4 \mathrm{m}^{2} \times 19.20$

                                               = 1351.68

Therefore width =35.2 m

Cost = Rs 1351.68/-