Question

find x:

3=9+3x/x²-1​

Answer 1

Answer:

x+1/x = root(13)

Simplifying the equation by taking LCM and cross multiplying, we get,

x^2-root(13)x+1 = 0,

D = [-root(13)]^2–4(1)(1) = 9,

x = [root(13)+3]/2, [root(13)-3]/2,

Consider any value of x and substitute in the given equation whose value you need to find because the answer will be same from both,

Let x = [root(13)+3]/2 and substitute,

3[root(13)+3]/2/{[root(13)+3]/2]^2–1},

3[root(13)+3]/2/(1/4)[13+9+6root(13)]-1,

3[root(13)+3]/2/[22+6root(13)-4]/4,

6[root(13)+3]/[6root(13)+18],

6[root(13)+3]/6[root(13)+3],

Answer 2

Step-by-step explanation:

3=9+3x/x2-1

3(x2-1)=9+3x

3x2-3=9+3x

3x2-3x=9+3

3x2-3x-12=0