Math, asked by adarsh8113, 1 year ago

Find x,y,z in the given parallelogram ABCD.

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Answered by sreeharsh
276

angle y = 45 degree

angle x = 70-y

= 25 deg

angle acd = 25

45 deg+25 deg + Z = 180

70 deg+z =180

z = 180 - 70

z= 110 deg

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Answered by mahajan789
3

Given, \angle DAC=45\° and \angle CBE=70\°

Now, \angle z+45\°+\angle x = 180\°...(1)(\because each pair of co-interior angles is supplementary)

\angle x=\angle ACD...(\because alternate angles)

\angle x+\angle y=70\° ....(2)(\because Sum of interior angles = exterior opposite angle)

\angle CBA=180\°-70\°=110\° (\because Supplementary angles)

\angle z=\angle CBA=110\° (\because Opposite angles in a parallelogram are equal)

From (1): \angle x=180\°-45\°-\angle z=135\°-110\°=25\°

From (2):\angle y=70\°-\angle x=70\°-25\°=45\°

Answer: \angle z=110\°, \angle x=25\°, \angle y=45\°

To learn more about the properties in the parallelogram, click on the following links:

https://brainly.in/question/51406908?msp_srt_exp=5

https://brainly.in/question/37999422?msp_srt_exp=5

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