Question

Five cells each of an

e.m.f. 2v and internal resistance 0.5ohm are connected in series. the resulting battery will have

Answer 1

v=ir
2=i×0.5
I=0.5/2
1/4
five cells are connected in series ,thus
1//4+1/4+1/4+1/4+1/4
5/4 or 1.25 ohm is the answer of this question

Answer 2

The resulting battery will have  1.25 Ω.

Explanation:

Given,

Voltage (V) = 2 V and internal resistance (R) = 0.5 Ω

To find, the resulting battery = ?

Apply Ohm's law,

V = IR

⇒ 2 = i × 0.5

⇒ $I =\dfrac{0.5}{2}=\dfrac{5}{20}=\dfrac{1}{4}$ Amp

The five cells are connected in series,

$=\dfrac{1}{4}+\dfrac{1}{4}+\dfrac{1}{4}+\dfrac{1}{4}+\dfrac{1}{4}$

$=\dfrac{5}{4}$ or 1.25 Ω

Hence, the resulting battery will have  1.25 Ω.