Five year ago,nuri was trice as old as sonu ten year later,nuri will be between twice as old as sonu how old as nuri and aonu
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Let the present age of Nuri = x year
And present age of Sonu = y year
Five years ago
Age of Nuri = x – 5 years
Age of Sony = y – 5 years
Nuri was thrice as old as Sonu
X- 5 = 3(y – 5)
X – 5 = 35 – 15
X – 3y = -15 + 5
X – 3 y = - 10 ………..(1)
Ten years later,
Age of Nuri = x + 10
Age of Sonu = y + 10
Nuri will be twice as old as Sonu.
X+ 10 = 2(y+10)
X + 10 = 2y + 20
X – 2y = 10 ………..(2)
X – 3 y = - 10 ………..(1)
Subtracting equation (1) from equation (2) we get
Y = 20
Plug this value in equation first we get
X - 3* 20 = -10
X = 60 – 10
X = 50
Hence age of Nuri = 50 years and age of Sonu = 20 years
thank u
Let the present age of Nuri = x year
And present age of Sonu = y year
Five years ago
Age of Nuri = x – 5 years
Age of Sony = y – 5 years
Nuri was thrice as old as Sonu
X- 5 = 3(y – 5)
X – 5 = 35 – 15
X – 3y = -15 + 5
X – 3 y = - 10 ………..(1)
Ten years later,
Age of Nuri = x + 10
Age of Sonu = y + 10
Nuri will be twice as old as Sonu.
X+ 10 = 2(y+10)
X + 10 = 2y + 20
X – 2y = 10 ………..(2)
X – 3 y = - 10 ………..(1)
Subtracting equation (1) from equation (2) we get
Y = 20
Plug this value in equation first we get
X - 3* 20 = -10
X = 60 – 10
X = 50
Hence age of Nuri = 50 years and age of Sonu = 20 years
thank u
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Answer:
Age of Nuri = 50 years
Age of Sonu = 20 years
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