For an Ap 1 upon 6. 1 upon 4. 1 upon 3 find 15th term and sum of first 10 terms
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AP 1/6,1/4,1/3.....
d=t2-t1= 1/4-1/6=3-2/12=1/6
a=1/6
an = a+(n-1)d (n=15)
a15 = 1/6 +(15-1)1/6
1/6+7/6
1+7/6 = 8/6=4/3
A15=4/3
the sum is (n=10)
Sn =n/2{2a+(n-1)d}
S10=10/2{2*1/6(10-1)*1/12}
5{1/3+9*1/12}
5{1/3+3/4}
5{4+9/12}
5{13/12}
65/12
S10=5.42
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