Chemistry, asked by baluramavath1487, 1 year ago

For the first two lines of paschen series ,identify the value of n1 and n2 .Calculate the wave number values for these lines ?

Answers

Answered by gadakhsanket
3
Hey dear,

● Answer -
Wave number for 1st and 2nd line in Paschen series are 5.33×10^5 /m and 7.11×10^5 /m respectively.

● Explanation -
For Paschen series, n1 = 3 & n2 = 4,5,6,...

For 1st line in Paschen series -
n1 = 3 & n2 = 4
ṽ = Rh (1/n1^2 - 1/n2^2)
ṽ = 1.097×10^7 (1/3^2 - 1/4^2)
ṽ = 5.33×10^5 /m

For 2nd line in Paschen series -
n1 = 3 & n2 = 5
ṽ = Rh (1/n1^2 - 1/n2^2)
ṽ = 1.097×10^7 (1/3^2 - 1/5^2)
ṽ = 7.11×10^5 /m

Therefore, wave number for 1st and 2nd line in Paschen series are 5.33×10^5 /m and 7.11×10^5 /m respectively.

Hope this helps you...
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