for what value of k the equation k x square+6x+1=0has equal roots?
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Answer:
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Step-by-step explanation:
This is the form ax
2
+bx+c=0
Here a=k,b=6,c=1
Δ=b
2
−4ac
Since the roots are equal, discriminant=b
2
−4ac=0.
Therefore, (6)
2
−4×k×1=0
⇒36−4k=0
⇒4k=36
⇒ k=
4
36
=9
⇒ k=9
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