Question

For what values of k, the zero of the polynomial 9x2+6kx+4 is 10?​

Answer 1

Answer:

Brother or sister I think you forgot and written x

Answer 2

Given

• p(x) = 9x² + 6kx + 4

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To find

• Value of k for which the zero of the given polynomial will be 10.

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Solution

• We need to find that value of k, for which the zero of given polynomial will be 10.

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$\: \: \: \: \sf\underline{Therefore\: we\: will\: put\: x = 10} \\ \: \: \: \: \: \: \sf\underline{in\: the\: given\: polynomial}$

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$\tt:\implies\: \: \: \: \: \: \: \: {p(x) = 9x^2 + 6kx + 4}$

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$\tt:\implies\: \: \: \: \: \: \: \: {p(10) = 9(10)^2 + 6k(10) + 4}$

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$\tt:\implies\: \: \: \: \: \: \: \: {p(10) = 9(100) + 60k + 4}$

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$\tt:\implies\: \: \: \: \: \: \: \: {p(10) = 900 + 60k + 4}$

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$\bf:\implies\: \: \: \: \: \: \: \: {p(10) = 904 + 60k}$

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★ If 10 is the zero of the given polynomial, then put

$\large{\boxed{\boxed{\sf{p(10) = 0}}}}$

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$\tt\longmapsto{904 + 60k = 0}$

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$\tt\longmapsto{60k = -904}$

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$\tt\longmapsto{k = \dfrac{-904}{60}}$

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$\bf\longmapsto{k = \dfrac{226}{15}\: or\: 15.06}$

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Hence,

• The Value of k is 226/15 or 15.06.

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