Question

Force of attraction between two point electric charges placed at a distance d in a medium is F. What distance apart should these be kept in the same medium, so that force between them becomes F//3?

Answer 1

$\underline{\boxed{ \huge\purple{ \rm{Answer}}}}$

Given :

Force between two charges = F

Distance between two charges = d

To Find :

Distance between two charges where Force becomes F/3

Formula :

As per coloumb's law Force between two charges is inversely proposnal to distance square.

mathematically

$\underline{ \boxed{ \bold{ \pink{ \rm{F \propto \frac{1}{ {r}^{2} }}}}}} \: \dag$

Calculation :

$\implies \rm \: \frac{F}{ (\frac{F}{3} )} = \frac{ {X}^{2} }{ {d}^{2} } \\ \\ \therefore \rm \: \frac{ {X}^{2} }{ {d}^{2} } = 3 \\ \\ \therefore \rm \: \frac{X}{d} = 3 \\ \\ \therefore \: \underline{ \boxed{ \bold{ \orange{ \rm{X = \sqrt{3} d}}}}} \: \: \purple{ \clubsuit}$