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In ∆PQC and ∆PRC
QC=PC. (Given)
PQ=CR. ( given)
PC=PC( common )
Therefore ∆pqc congruent ∆ PRC by sss axiom
Hence angle PCQ = angle PCR. ( by cpct)
Proved...
QC=PC. (Given)
PQ=CR. ( given)
PC=PC( common )
Therefore ∆pqc congruent ∆ PRC by sss axiom
Hence angle PCQ = angle PCR. ( by cpct)
Proved...
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