Question

From a point P on the ground the angle of elevation of a 10 m tall building is 30°. A flag is hoisted at the top of the building and the angle of elevation of the top of the flag-staff from P is 45°. Find the length of the flag-staff and the distance of the building from the point P. (Take 3=1.732).

Answer 1

Answer:

The length of a flag staff is 7.32 m and the distance of the building from the point P is 17.32 m

Step-by-step explanation:

Let the length of a flag staff be AB (h) and the length of the building , BC be 10 m.

Let the distance of the building from the point P is y.

The angle of elevation of the top of the flag-staff from P is ∠APC = 45° and the angle of elevation of a 10 m tall building from P is ∠BPC = 30°

In right angle ∆BCP,

tan 30° =  P/B = BC/CP

1/√3 = 10/y

y = 10√3  

y = 10 × 1.732

[√3 = 1.732]  

y = 17.32 m ………..(1)

In right angle ∆ACP,

tan 45° =  P/B = AC/CP

1 = (AB + BC)/CP

1 = (h + 10) /y

1 = (h + 10)/17.32

[From eq 1]

17.32 = h + 10

h = 17.32 - 10

h = 7.32 m  

Hence, the length of a flag staff is 7.32 m and the distance of the building from the point P is 17.32 m

HOPE THIS ANSWER WILL HELP YOU…

Answer 2

Answer:

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