give me answere 14?????????
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arpityadav9559:
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8x=pie
7x+x=pie
7x=pie-x :taking cos both sides
cos7x=cos(pie-x)
cos7x=-cos(pie)
so you got the value of cos7x now put on this to 2nd equation ie
cos7x+cosx=-cosx+cosx =0 hence proved ❤
7x+x=pie
7x=pie-x :taking cos both sides
cos7x=cos(pie-x)
cos7x=-cos(pie)
so you got the value of cos7x now put on this to 2nd equation ie
cos7x+cosx=-cosx+cosx =0 hence proved ❤
Answered by
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Let me take @ as x for convenience.
Hence, 8x = pi.
x = pi/8.
.
Therefore LHS of To prove:-
.
= Cosx + Cos(7x)
= Cos(pi/8) + Cos (7pi/8)
= Cos(pi/8) + Cos[(8pi - pi)/8]
= Cos(pi/8) + Cos[pi - (pi/8)]
Here Cos(pi - pi/8) = -Cos(pi/8).
= Cos(pi/8) + Cos(pi - pi/8)
= Cos(pi/8) - Cos(pi/8)
= 0
= RHS
it may help u plsssszz mark it as branliest
Hence, 8x = pi.
x = pi/8.
.
Therefore LHS of To prove:-
.
= Cosx + Cos(7x)
= Cos(pi/8) + Cos (7pi/8)
= Cos(pi/8) + Cos[(8pi - pi)/8]
= Cos(pi/8) + Cos[pi - (pi/8)]
Here Cos(pi - pi/8) = -Cos(pi/8).
= Cos(pi/8) + Cos(pi - pi/8)
= Cos(pi/8) - Cos(pi/8)
= 0
= RHS
it may help u plsssszz mark it as branliest
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