give the correct answer
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Answer:
Step-by-step explanation:
3) The greatest 4 digit number divisible by 18, 24 and 32 is 9504 and
4) L.C.M of 8, 10, 12 = 2 x 2 x 2 x 3 x 5 = 120.
the smallest 4 digit number = 1000
The smallest four digit number that is divisible by 120:
120x8= 960
120 x 10 = 1200
Since 120 is divisible by 8, 10 and 12, 1200 is also divisible by all these numbers.
Therefore, 1200 is the smallest four digit number divisible by 8, 10 and 12.
In order to find the smallest 4-digits number exactly divisible by 18,24 and 32.We need to find the LCM of 18,24and 32.
The smallest 4-digits number=1000
The smallest 4-digits number exactly divisible by 18,24 and 32= ?
Now ,whatever is the LCM divide it by the smallest 4-digits number which is 1000.
Lets take the LCM of 18,24 and 32 as x .
Now divide x with 1000
Now whatever is the quotient add 1 in that and multiply it with x then you will get the smallest 4-digits number exactly divisble by 18,24 and 32.
See, I didnt took the LCM because it would take much time to answer thats why you will take out the LCM and then solve .
You need to solve q4 like this pattern only .
In order to find the greatest 4-digit no. We need to subtract 18 from each no.
Now whatever no. you get after subtraction ,
Factorize them and see which are the common factors then after that find that which is the Greatest common factor among them and GCF greatest common factor of the no. after subtraction is the greatest four digits no. leaving 18 in each case .
For q6 find out the LCM of 63,70 and 77 .
The LCM of these is the minimum distance .
After finding the LCM write cm because they were in the unit of cm .
Hope you understood,
Thank you