Question

Given: a²+1/a²=7 and a≠0 , find :
1. a+1/a
2. a-1/a
3. a²-1/a²​

Answer 1

Answer:

1

-1

-1

here is your answer

Answer 2

Answer:

1. (a+1/a) ²=a²+1/a²+2

Write the formula first

Then substitute the given value

(a+1/a²) =7+2

(a+1/a²) =9

when the square goes from L.H.Sto R.H.S then it will be Square root

So,

(a+1/a)=√9

Finally, a+1/a=3

2. (a-1/a)²=a²+1/a²-2

Substitute the given values in the above formula

(a-1/a)²=7-2

(a-1/a)²=5

Finally, (a-1/a) =√5