greatest 3 digit number divisible by 6,8,12
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6=2*3
8=2*2*2
12=2*2*3
So the number must be divisible by 8 and the sum of its digits must be divisible by 3.
Greatest 3 digit number=999
By moving backwards constantly by trial and error method we get the following answer:984.
8=2*2*2
12=2*2*3
So the number must be divisible by 8 and the sum of its digits must be divisible by 3.
Greatest 3 digit number=999
By moving backwards constantly by trial and error method we get the following answer:984.
AcharyaVII:
yessir
thn y answer is being deleted!!
U did not show the procedure....maybe you merely copied my answer...thats the case
hein?? kuch bhi !!
matlab??????
maine solve kiya tha apni copy pe tb idhr dala tha aur jo mujhe aata nhi wo mai dalti nhi to cheat krne ka koi chance hi nhi h
accha par tumhe procedure -bhi dikhana chahiye tha
chalo koi nhi jane do
same hi tarika h
ha.....
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