greatest 3 digit number divisible by 6,8,12
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6=2*3
8=2*2*2
12=2*2*3
So the number must be divisible by 8 and the sum of its digits must be divisible by 3.
Greatest 3 digit number=999
By moving backwards constantly by trial and error method we get the following answer:984.
8=2*2*2
12=2*2*3
So the number must be divisible by 8 and the sum of its digits must be divisible by 3.
Greatest 3 digit number=999
By moving backwards constantly by trial and error method we get the following answer:984.
AcharyaVII:
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