Question

hay!!

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if k+2,4k-6,3k-2,....................AP



find the value of k


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Answer 1

hii..

Condition for an AP is 2b = a + c

so, here let a = K + 2 ( which is first term ) , b = 4k - 6 ( 2nd term ) , c = 3k - 2 ( third term )

then,

2 ( 4k - 6 ) = k + 2 + 3k - 2

8k - 12 = 4k

4k = 12

k = 3 ans.

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Hope this helps !

Answer 2

Hey dear !!

Here is your answer !!

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Given ->

↪k-2 , 4k - 6 ,3k -2 are in AP.

Solution ->

↪These are the three consecutive terms of an AP.

↪4k - 6 - (k +2) = 3k -2 - (4 k -6)

↪4k - 6 -k -2 = 3k -2 - 4k + 6

↪4k - k -6 -2 = -4k + 3k -2 + 6

↪3k - 8 = -k + 4

↪3k + k = +4 +8

↪4k = +12

↪k = 12 / 4

↪k = 3

Hope it is satisfactory ^_^

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