Question

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Solve:(X-A)(X-B)...(X-Z)

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Answer 1

$\boxed{\huge{\texttt{\fcolorbox{red}{yellow}{Hello!!}}}}$

Happy Chhath To You Too!

Now, Come to the Question

Question
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Solve:(X-A)(X-B)...(X-Z)

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Given that,

Solve:(X-A)(X-B)...(X-Z)

Now, Though the question, It seems to be tricky but it's quiet easy!!

In the series, One term would also come i.e (X-X) and the result of that term will be Zero(0).

Thus, The rest of the terms multiplied with zero, the final answer turns out to be zero(0).

Therefore, (X-A)(X-B)...(X-Z) = 0.

$\huge{\mathfrak{\underline{\underline{\underline{Hope It Helps!!!}}}}}$

Answer 2

Given equation : (X - A )( X - B ).....( X - Z ).

From the given sequence, we get that given sequence is the product of difference of all the alphabets from X.

So, equation should be like : ( X - A )( X - B )( X - C ).....( X - X )( X - Y )( X - Z ).

Now, clearly we can see that the given equation contains ( X - X ) too.

We know that the result of subtraction of any number from itself is 0.

∴ X - X = 0

Now,

Equation is ( X - A )( X - B )( X - C )..........( 0 )( X - Y )( X - Z )

We know that any number multiply by 0 is equal to 0.

∴ ( X - A )( X - B )( X - C ).........0( X - Y )( X - Z ) = 0

Therefore, value of (X - A )( X - B ).....( X - Z ) is 0.

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