Question

Hey Only geniuses can solve this..

This is an integer type question ...

A compound h2x with molar weight of 80 gram is dissolved in solvent having density of 0.4 gram ml assuming no change in volume up on dissolution the molarity of a 3.2 molar solution is ??

Answer 1

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So, this question can be solved by conversion of Molarity into molality

As we know that ,

Molarity = 3.2 M

let volume of solution = 1000ml = Volume of solvent

Mass of solvent = 1000 × 0.4 = 400 g

since, Molarity of solution = 3.2 molar

so, N(solute) = 3.2 mol

Molarity (m) =

$\frac{3.2}{ \frac{400}{1000} } = \frac{3.2 \times 1000}{400} = 8$
Hence, Correct integer by solving is 8


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Answer 2

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According to question we have given;

Amount of solute (Molarity) = 3.2 molar

Volume of solvent = 1 lit.

Density = 0.4 g/mol

Now,

Density = $\dfrac{Mass}{Volume}$

Mass of solvent = Density × Volume

= (0.4 g/mol) × (1.0 lit.)

= (0.4 g/mol) × (1000 ml)

= 400.0 g

= 0.4 kg

Now we have to find Molarity...

So,

Molarity = $\dfrac{Number\:of\: moles\:of\:solute}{Volume\:of\:solution\:in\:ml}$

Molarity = $\dfrac{3.2}{0.4}$

Molarity = 8 mol/kg or Molar

$\textbf{Molarity = 8 Molar}$

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