Question

How do you find the solution to the quadratic equation 2x2+3x−3=0?

Answer 1

Answer:

$x=\dfrac{-3+\sqrt{33}}{4}$

$x=\dfrac{-3+\sqrt{33}}{4}$

Step-by-step explanation:

We can find the solution to the quadratic equation:

2x² + 3x - 3 = 0

It is in the form ax² + bx + c = 0, where

a = 2

b = 3

c = -3

$=\frac{-b\pm\sqrt{b^{2}-4ac}}{2a}\\\\=\frac{-3\pm\sqrt{3^{2}-4*2*(-3)}}{2*2}\\\\=\frac{-3\pm\sqrt{9+24}}{4}\\\\ =\frac{-3\pm\sqrt{33}}{4}$

Now, solve for x;

$x=\dfrac{-3+\sqrt{33}}{4}$

$x=\dfrac{-3-\sqrt{33}}{4}$