Math, asked by arfas743, 1 year ago

How do you solve 8−3r≤5−2r?

Answers

Answered by kanika1809
3

Answer:

step by step explanation:

8 - 5 \leqslant  - 2r + 3r \\ 3 \leqslant r \\ r \geqslant 3

hope it helps

thanks

Answered by Anonymous
0

HEY MATE HERE IS YOUR ANSWER--

8−5⩽−2r+3r

3⩽r

r⩾3

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