Math, asked by Wulf, 3 months ago

How do you solve
2xsquared + 3× −3 = 0
using the quadratic formula?

Answers

Answered by ASHCAD
1

Answer:

0.685 OR -2.185

Step-by-step explanation:

2x² + 3x - 3 = 0

a (co-efficient of x²) = 2

b (co-efficient of x) = 3

c (constant) = -3

b²-4ac = 3² - (4×2×-3)

= 9 - (-24)

= 9 + 24

= 33

√(b² - 4ac) = √33 = 5.74

x = [-b ± √(b² - 4ac)] / 2a

= (-3 ± 5.74) / 4

= (-3 + 5.74)/4 OR (-3 - 5.74)/4

= 2.74/4 OR -8.74/4

= 0.685 OR -2.185

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