how many 4 digit numbers are there , without repetition of digit ,if each number is divisible by 5
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First digit possibilities- 9 (1,2,3,4,5,6,7,8,9)
Second digit possibilities- 9 (0,1,2,3,4,5,6,7,8,9 except the first digit)
Third digit possibilities- 8 (0,1,2,3,4,5,6,7,8,9 except the first and second digit)
Fourth digit possibilities- 2 (5,10)
Therefore, 9×9×8×2
== 1296
Second digit possibilities- 9 (0,1,2,3,4,5,6,7,8,9 except the first digit)
Third digit possibilities- 8 (0,1,2,3,4,5,6,7,8,9 except the first and second digit)
Fourth digit possibilities- 2 (5,10)
Therefore, 9×9×8×2
== 1296
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