how many aluminium ions are present in 0.0519 g of aluminium oxides?
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Aluminium oxide is : Al2 O3
Molecular mass = 102 units
in 102 grams we have Na = avogadro number of molecules => 2 * Na atoms of Aluminum or 2 * Al ions.
So number of ions = 2 * 0.0519 / 102 * 6.0225 * 10^23
= 6.128 * 10^20
Molecular mass = 102 units
in 102 grams we have Na = avogadro number of molecules => 2 * Na atoms of Aluminum or 2 * Al ions.
So number of ions = 2 * 0.0519 / 102 * 6.0225 * 10^23
= 6.128 * 10^20
nope:
why its multiplied by 2
there are two aluminum atoms in one molecule. so there are two ions of Al per molecule of aluminum oxide.
ok so we dont need the atomic mass of al
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