Question

How many tiles are required to cover a floor of length 6 m and breadth 4 m, if the area covered by each tile is 400 sq. cm?

Answer 1

Area of floor =l × b=6m×4m
=600cm*400cm=240000cm^2
No. Of tiles= total area of floor/ area covered by each tile
No. Of tiles=240000/400=600 tiles

Answer 2

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600 tiles are required

Length of floor = 6 m = 600 cm

Breadth of floor = 4 m = 400 cm

Area of floor = Length \times Breadth×Length×Breadth

Area of floor = 600 \times 400600×400

Area of floor = 240000 cm^2240000cm

2

Area requires by 1 tile = 400 sq.cm.

No. of tiles required for the floor =

$\frac{240000}{400}$

400

240000

= 600600

Hence 600 tiles are required .