how many two digit numbers are there which leave remainder 4 on division by 6
Answers
Answered by
0
Answer:
18
Step-by-step explanation:
The two-digit numbers which leave the remainder 1 when divided by 5 are ;
11,16,21,26,.......86,91,96
In this A.P :
a = 11
d = 16-11 = 5
l = 96
n = ?
Tn = a+(n-1)d
96 = 11+(n-1)5
n-1 = 85/5
n = 17+1
n = 18
Hence their are 18 two digit numbers which when divided by 5 leaves remainder 1.
Answered by
1
Answer:
10,16,22,34,46and more
Step-by-step explanation:
add 4 to every no. which is divisival by six
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