how to solve it ???
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please mark as brainliest
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Given,
OA = OC
∠AOB = ∠COD
∠BAO = ∠DCO
⇒ ΔAOB ≡ ΔCOD BY ASA PROPERTY
∴By (I forgot the name) theorem,
AB = DC
OB = OD
⇒ 17 = 3x + 2
15 = 3x
x = 5
19 = 2y + 7
12 = 2y
y = 6
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