Question

i will mark u as brainliest

Answer 1

heyy mate here is ur ans!!!....

$\frac{ \tan(theta) + \sec(theta) - 1 }{ \tan - \sec - 1 }$

$\frac{ \ \sec + \tan - ( { \sec }^{2} - { \tan }^{2}) }{ \tan - \sec + 1 }$

$\frac{ \sec + \tan - ( \sec - \tan)( \sec + \tan)}{ \tan - \sec + 1 }$

cancel out ....1-sec+tan

now!!
sec+tan=

$\frac{1}{ \cos } + \frac{ \sin}{ \cos}$

therefore RHS = ...

1+SIN/COS

HENCE PROVED...✌✌


hope it helps ...
mark as brainliest plezzzzz!!!✌✌